How do I find the limit as #x# approaches negative infinity of #cosx#? Precalculus Limits Limits Involving Infinity 1 Answer Wataru Dec 12, 2014 Since #cos x# does not approach any particular number as #x# approaches #-infty#, #lim_{x to -infty}cos x# does not exist. I hope that this was helpful. Answer link Related questions How do I find the limit as #x# approaches infinity of #(1.001)^x#? How do I find the limit as #x# approaches infinity of #x^7/(7x)#? How do I find the limit as #x# approaches infinity of #xsin(1/x)#? How do I find the limit as #x# approaches infinity of the square root function? How do I find the limit as #x# approaches infinity of #tanx#? What is the limit as #x# approaches infinity of #(x^2-4)/(2x-4x^2)#? What is the limit as #x# approaches infinity of #1/x#? What is the limit as #x# approaches infinity of #x#? What is the limit as #x# approaches infinity of #cosx#? What is the limit as #x# approaches infinity of #lnx#? See all questions in Limits Involving Infinity Impact of this question 6329 views around the world You can reuse this answer Creative Commons License