What is the limit as #x# approaches infinity of #lnx#?

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Feb 17, 2015

First of all it is important to say that #oo#, without any sign in front of, would be interpreted as both, and it is a mistake!

The argument of a logarithmic function has to be positive, so the domain of the function #y=lnx# is #(0,+oo)#.

So:

#lim_(xrarr+oo)lnx=+oo#, as shown by the graphic.

graph{lnx [-10, 10, -5, 5]}

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