# What is the limit as #x# approaches infinity of #(x^2-4)/(2x-4x^2)#?

##### 2 Answers

Mar 22, 2018

Mar 22, 2018

#### Answer:

#### Explanation:

#"divide terms on numerator/denominator by the highest"#

#"power of x, that is "x^2#

#rArr(x^2/x^2-4/x^2)/((2x)/x^2-(4x^2)/x^2)=(1-4/x^2)/(2/x-4)#

#rArrlim_(xtooo)(x^2-4)/(2x-4x^2)#

#=lim_(xtooo)(1-4/x^2)/(2/x-4)#

#=(1-0)/(0-4)=-1/4#