# How do I find the limit as x approaches negative infinity of sinx?

$L i m x \to - \infty$ sin x = $L i m x \to \infty$ sin(-x)= $L i m x \to \infty$ -sinx
As $x \to \infty$, sin x will oscillate between -1 and +1 and will not converge to any particular value. Hence this limit would not exist.