How do I find the range of the function #y=-2^x+2#? Precalculus Functions Defined and Notation Range 2 Answers Antoine Apr 22, 2015 Here's my attempt: #y<2# is the range. #y=-2^x+2# Can also be written as #2-y=2^x# and also, #ln(2-y)=xln2# #=> 2-y>0 => y<2# Hubert May 21, 2015 The range of #y=-2^x+2# is #(-infty;2)#. I'd start from a known fact that #a^x>0# for all #a>0# and #x in RR#. So: #2^x>0# #-2^x<0# #-2^x+2<2# #y<2# #y in (-infty;2)# Related questions What is the range of a function? What are some examples of range? How does the range of a function relate to its graph? What are common mistakes students make when working with range? How does the range of a function relate to its y-values? What is the range of a linear function? What is the range of a quadratic function? What is the range of a function like #f(x)=5x^2#? What is the range of a function like #f(x) = sqrt (x-5)#? How do I find the range of the function #f(x)=10-x^2#? See all questions in Range Impact of this question 1332 views around the world You can reuse this answer Creative Commons License