How do I find the vertex, axis of symmetry, y-intercept, x-intercept, domain and range of #v(t) = t^2 + 11t - 4#?
Please see the solution below.
The axis of symmetry is the same as the x-coordinate of the vertex, so in this case:
To find the y-intercept set x to zero and solve for y, in this case:
To find the x-intercepts set y to zero and solve for x:
The domain of parabola is all the real numbers, but the range is limited by y-coordinates of the vertex, in this case since the parabola opens up the vertex is the minimum so the range is: