How do I find the vertex of #f(x)=x^2-4x+3#?
We must take our equation and put it in vertex form,
This equation will not factor into two squares
First we'll get rid of the
Next we take half of the -4 the square it and add it to our equation to give us
Now we can factor the left into two perfect squares,
Finally, we subtract
The easiest way to determine the vertex of this parabola is using a formula.
From the function,
a = 1 b = -4 c = 3
to get k, substitute the value of h for x into the function