How do I find the vertex of #f(x)=x^2-8x+7#?
2 Answers
To find the vertex of
The first thing you want to do is determine the axis of symmetry (the x co-ordinate of the vertex). To do this, you must factor the equation. In order to factor this simple trinomial, you want to determine 2 numbers that add to give you -8, and multiply to give you +7. These two numbers are -1 and -7:
-7 x -1 = +7
-7 + -1 = -8
Now, you take these two factors and put them in brackets, each with an x like so:
Now, set each bracket equal to zero and solve. You should get x = 7 and x = 1. To determine the axis of symmetry, simply add the zeros together and divide by 2:
Therefore, the equation for the axis of symmetry is x=4
Now to determine the optimal value (y co-ordinate of the vertex), you can substitute the axis of symmetry into the equation (either the factored form or the original; in this case, factored would me the simplest):
Putting it together, the vertex is (4, -9)!
Hopefully this was of some help and hopefully you've understood all this! For a faster method, look up "completing the square - vertex form"! :)
Another method!
Explanation:
Given:
This is already in the form
So we can do this 'trick'
Applying
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Substitute for
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