How do I find the x-intercepts of the graph of y=x^2-3x-10? Precalculus Geometry of a Parabola Graphing Parabolas 1 Answer Ernest Z. Jul 9, 2015 You set y = 0 and solve for x. y = x^2-3x-10 = 0 (x-5)(x+2) = 0 x-5 = 0 or x+2 = 0 x = 5 or x = -2 The x-intercepts are at (5,0) and (-2,0). Answer link Related questions What is the graph of the parabola represented by y=2x^2-8x+9? What is the parent graph of a parabola? How do I find the axis of the graph of the function f(x)=4x^2+8x+7? What is the graph of f(x)=-2x^2+7x+4? What is the x-intercept of the graph of y=x^2-4x+4? What is the vertex of the graph of y=x^2+3x-4? What is the vertex of the graph of y=2(x-3)^2-7? What is the vertex of the graph of y=-(x-2)^2+3? What is the axis of symmetry of the graph of y=-(x+3)^2-6? How do I graph y=x^2-2x-3? See all questions in Graphing Parabolas Impact of this question 3018 views around the world You can reuse this answer Creative Commons License