# How do I graph the hyperbola represented by #(x-2)^2/16-y^2/4=1#?

##### 1 Answer

Apr 22, 2017

#### Answer:

Analyze the terms of the function given.

#### Explanation:

Since the y term of this equation is negative and the x term is positive, we know that this is a hourglass shaped graph and not a baseball shaped graph. The formula for a hyperbola is as follows:

h is the distance the graph is shifted from the y-axis

k is the distance the graph is shifted from the x-axis.

a is the distance from the vertex of the graph to the center of the graph

b is used to indicate vertical stretch

A correlation between variables is

graph{(((x-2)^2)/16)-((y^2)/4)=1 [-10, 10, -5, 5]}