# Where should I draw the asymptotes of (x+2)^2/4-(y+1)^2/16=1?

Oct 11, 2015

Since the positive term includes the variable x, this hyperbola opens up along the x-axis. The equation for the asymptotes is $y = \pm \frac{b}{a} \left(x - h\right) + k$

#### Explanation:

$a = \sqrt{4} = 2$
$b = \sqrt{16} = 4$
$h = - 2$, $k = - 1$

$y = \pm \frac{b}{a} \left(x - h\right) + k$

$y = \pm \frac{4}{2} \left(x + 2\right) - 1$

hope that helped