How do I graph the hyperbola with the equation #4x^2−y^2+4y−20=0?#?
1 Answer
Aug 14, 2018
Please see the explanation below
Explanation:
You need the center, the vertices and the asymptotes.
The equation is
Dividing by
Comparing this to the general equation of a hyperbola
The center is
The vertices are
and
And the asymptotes are
Now, you can plot the graph
graph{(4x^2-y^2+4y-20)(y-2-2x)(y-2+2x)=0 [-15.77, 16.27, -5.8, 10.2]}