How do I solve the rational inequality #(x^2-1)/(x+1)<2# using a TI-83?

1 Answer
Jul 8, 2015

Answer:

You can input #Y1=#function, #Y2=2# and use intercept.

Explanation:

But you can also do this on a piece of paper.
If you factorise the denominator, you get:

#((x-1)cancel((x+1)))/cancel(x+1)<2#

And you can cancel out the #x+1#'s on the condition that #x!=-1# (but that value of #x# was already 'forbidden').

We are now left with: #x-1<2->x<3#

Complete answer: #x<3andx!=-1#
graph{(x^2-1)/(x+1) [-10, 10, -5, 5]}