How do I use the quadratic formula to solve #x^2 + 8x = 2#?

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Answer 1 · 2014-09-30T03:08:31

#Ax^2+Bx+C=0#

#x^2+8x=2#

#x^2+8x-2=0#

#A=1, B=8, C=-2#

Quadratic Formula, #x=(-b+-sqrt(b^2-4ac))/(2a)#

#x=(-(8)+-sqrt((8)^2-4(1)(-2)))/(2(1))#

#x=(-8+-sqrt(64+8))/(2)#

#x=(-8+-sqrt(72))/(2)#

#x=(-8+-sqrt(2*2*2*3*3))/(2)#

#x=(-8+-(2)*(3)*sqrt(2))/(2)#

#x=-4+-(3)*sqrt(2)#

#x=-4+-3sqrt(2)#