How do y simplify $\sqrt{648}$ $sqrt648$ ?

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Answer 1 · 2016-07-02T22:55:40

$18 \sqrt{2}$ $18sqrt2$

Write 648 as the product of its prime factors first:

$\sqrt{648} = \sqrt{2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 3 \times 3}$ $sqrt648 = sqrt(2xx2xx2xx3xx3xx3xx3xx3)$

= $\sqrt{2 \times 2^{2} \times 3^{4}}$ $sqrt(2 xx 2^2 xx 3^4)" "$ group even powers where possible.

= $2 \times 3^{2} \sqrt{2}$ $2xx 3^2 sqrt2$

= $18 \sqrt{2}$ $18sqrt2$

How do y simplify √648sqrt648?