How do y simplify #sqrt648#?

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Answer 1

Jul 2, 2016

#18sqrt2#

Write 648 as the product of its prime factors first:

#sqrt648 = sqrt(2xx2xx2xx3xx3xx3xx3xx3)#

=#sqrt(2 xx 2^2 xx 3^4)" "# group even powers where possible.

=#2xx 3^2 sqrt2#

= #18sqrt2#