N_2 + 3H_2 ---> 2NH_3 What volume of hydrogen is necessary to react with five liters of nitrogen to produce ammonia? (Assume constant temperature and pressure.)
N_2 + 3H_2 ---> 2NH_3 , as per this equation, 1 volume of Nitrogen , needs 3 volumes of Hydrogen. The reaction produces two volumes of ammonia.
Let us write this as equation;
"1 volume of Nitrogen"/"3 volume of Hydrogen" (a)
If we start with 5 L of Nitrogen , X volumes of Hydrogen will be needed.
Let us write this as equation;
"5 L of Nitrogen"/"X L of Hydrogen" (b)
equate (a) and (b)
1/3 = 5/X
cross multiply 1 * X = 3 * 5 , X=15 L
2CO + O_2 ---> 2CO_2 How many liters of carbon dioxide are produced if 75 liters of carbon monoxide are burned in oxygen? How many liters of oxygen are necessary?
As per this equation, 2 volumes of Carbon Monoxide, needs 1 volume of Oxygen. The reaction produces two volumes of Carbon dioxide.
Let us write this as equation;
"2 volume of Carbon Monoxide"/"2 volumes of Carbon Dioxide" (a)
If we start with 75 L of Carbon monoxide , X volumes of carbon dioxide will be produced.
Let us write this as equation;
"75 L of CO"/("X L of "CO_2) (b)
equate (a) and (b)
2/2 = 75/X
cross multiply 2*X = 2*75 , X= 75 L
"2 volume of Carbon Monoxide"/"1 volumes of Oxygen" (a)
If we start with 75 L of Carbon Monoxide , X volumes of Oxygen will be needed.
"75 L of CO"/("X L of "O_2) (b)
equate (a) and (b)
2/1= 75/X
2*X = 75*1
2X =75
X= 37.5 L