When 10.0 mL of AgNO3 solution is treated with excess amount of HI gas to give 0.235 g of AgI, what is the concentration of the AgNO3 solution?
The concentration of the AgNO₃ solution is 0.100 mol/L.
There are three steps to this calculation.
- Write the balanced chemical equation for the reaction.
- Convert grams of AgI → moles of AgI → moles of AgNO₃.
- Calculate the molarity of the AgNO₃.
AgNO₃ + HI → AgI + HNO₃
Moles of AgNO₃ = 0.235 g AgI ×
Molarity of AgNO₃=
The molarity of the AgNO₃ is 0.100 mol/L.