If 100 mL of HCl gas at 300 K and 200 kPa dissolved in pure water requires 12.50 mL of the NaOH solution to neutralize in a titration experiment, what is the concentration of the NaOH solution?
The concentration of the NaOH solution is 0.641 mol/L.
There are four steps to this calculation.
- Write the balanced chemical equation for the reaction.
- Calculate the moles of HCl.
- Convert moles of HCl → moles of NaOH.
- Calculate the molarity of the NaOH.
HCl + NaOH → NaCl + H₂O
Moles of NaOH = 8.019 × 10⁻³ mol HCl ×
Molarity of NaOH =
The molarity of the NaOH is 0.641 mol/L.