# How do you balance C_4H_8 + O_2 -> CO_2 + H_2O?

Dec 22, 2016

$\text{Garbage in equals garbage out.......}$
${C}_{4} {H}_{8} + 6 {O}_{2} \rightarrow 4 C {O}_{2} \left(g\right) + 4 {H}_{2} O \left(g\right)$
Can you do same for $\text{pentane}$, ${C}_{5} {H}_{12}$? It is a little harder to balance.