# How do you calculate log_2 8^2 ?

Apr 14, 2016

${\log}_{2} \left({8}^{2}\right) = 6$
${\log}_{2} \left({8}^{2}\right)$ can be written as
${\log}_{2} \left({\left({2}^{3}\right)}^{2}\right)$
= ${\log}_{2} \left({2}^{6}\right) = 6 {\log}_{2} \left(2\right) = 6 \cdot 1 = 6$