How do you calculate #log_3 -4.8# with a calculator?

1 Answer
Feb 14, 2017

Answer:

Assuming that you want to take the #log# of #-4.8# to the base #3#, this expression is mathematically invalid.

Explanation:

It is impossible to take the #log# of #x# where #x<=0#. This is because, for any non-zero constant, #x#, there is no power we can raise it to so that it becomes equal to or less than #0#.