How do you calculate the derivative for h(t) = t^3 + 2e^t?

Mar 2, 2018

h´(t)=3t^2+2e^t

Explanation:

Because:

A constant is "neutral" for derivative (linearity)

the derivative of ${x}^{n}$ is n·x^(n-1)

And The derivative of ${e}^{x}$ is itself, ${e}^{x}$