# How do you calculate the formal charge on each atom in O_3?

Nov 5, 2016

By drawing the Lewis structure of the molecule. Formal charge separation is observed.

#### Explanation:

Each oxygen atom contributes 6 valence electrons to the ${O}_{3}$ molecule, and thus we have to account for 9 electron pairs.

A Lewis structure of ""^(-)O-O^(+)=O is reasonable, where from left to right as written each oxygen atom is associated with $7$, $5$, and $6$ electrons.

Since in each oxygen atom there are 8 nuclear protons, and 2 inner core electrons, around each oxygen atom there are $9$, $7$, and $8$ electrons, which accounts for the individual formal charges.

So what is the shape of the molecule if the central oxygen has a lone pair, a double bond, and a single bond?