# How do you calculate the height of a column of carbon tetrachloride, C Cl_4(l), with a density of 1.59 g/mL that exerts the same pressure as a 15.2 cm column of Mercury, Hg(l), that has a density of 13.6 g/ml?

Nov 2, 2016

You can do it like this:

#### Explanation:

The pressure caused by the fluid is given by:

$\textsf{P = \rho g h}$

$\textsf{\rho}$ is the density

$\textsf{g}$ is the acceleration due to gravity

$\textsf{h}$ is the height of the column

Since the pressures are equal we can write:

$\textsf{{\rho}_{1} \cancel{g} {h}_{1} = {\rho}_{2} \cancel{g} {h}_{2}}$

$\therefore$sf(h_(1)=(rho_(2)h_(2))/(rho_(1))

$\textsf{{h}_{1} = \frac{13.6 \times 15.2}{1.59} = 130 \textcolor{w h i t e}{x} \text{cm}}$