How do you calculate the mass of HCI required to prepare 2.5 liters of a 0.08 molar solution of HCI?

1 Answer
Aug 26, 2016

Answer:

Easy.

Explanation:

#2.5# #liters# of a #0.08# #molar# solution of #HCI# gives us #mol##es# of #HCl# in the solution

#Molarity#*#Volume# = #mol##es#

#0.08# #(mol)/cancel L# * #2.5 cancel L# = #0.2 mol##es# #HCl#

Now you must convert #mol##es# to #grams#

#Molar# #mass# of #HCl#
#H = 1.01 (g)/(mol)#
#Cl = 35 (g)/(mol)#

#HCl = 1+35=36(g)/(mol)#

#(0.2 cancel mol)/1# * #36 (g)/(cancel mol)# = #color (red) (7.2 g)# #HCl#