How do you calculate the pH of 0.075M KOH?

1 Answer
May 17, 2017

Answer:

#pH=12.88#

Explanation:

We know #(i)# that #pH+pOH=14# in aqueous solution under standard conditions...........

We also know #(ii)# that #pOH=-log_10[HO^-]#

#=-log_10(0.075)=-(-1.12)=+1.12#.

And so #pH=14-pOH=12.88#