# How do you classify the conic #x^2+4y^2-8x+3y+12=0#?

##### 1 Answer

Jan 20, 2017

#### Explanation:

Let the equation be of the type

then if

**parabola**

**circle**

**ellipse**

**hyperbola**

In the given equation

Therefore,

Hence,

graph{x^2+4y^2-8x+3y+12=0 [1.302, 6.302, -1.64, 0.86]}