# How do you combine (5b^2 + 3b) + (b^2 - 2b)?

Apr 3, 2018

$6 {b}^{2} + b$

#### Explanation:

$\left(5 {b}^{2} + 3 b\right) + \left({b}^{2} - 2 b\right)$
=$5 {b}^{2} + 3 b + {b}^{2} - 2 b$
= $6 {b}^{2} + b$

Apr 3, 2018

the answer is $5 {b}^{4} - 7 {b}^{3} - 6 {b}^{2}$

#### Explanation:

first you have to distribute $5 {b}^{2}$ to everything on the other sides so:$5 {b}^{2} \cdot {b}^{2}$ and $5 {b}^{2} \cdot - 2 b$ and now do the same for $3 b$ so you'll have$3 b \cdot {b}^{2}$ and $3 b \cdot - 2 b$ and all together:$5 {b}^{4} - 10 {b}^{3} + 3 {b}^{3} - 6 {b}^{2}$ and now combine like terms. combine terms with the same exponents and you get your answer

Apr 3, 2018

$6 {b}^{2} + b$

#### Explanation:

So this is actually a really simple question.

First off you got to distribute the plus sign.

$\left(5 {b}^{2} + 3 b\right) + {b}^{2} - 2 b$

Now you just add like terms.

$5 {b}^{2} + {b}^{2} + 3 b - 2 b$

$6 {b}^{2} + b$