How do you complete the square for 8x^2 -160x + 560?

Jul 7, 2015

Solve $y = 8 {x}^{2} - 160 + 560 = 0$

Explanation:

$y = 8 \left({x}^{2} - 20 x + 70\right) = 0$

$\left({x}^{2} - 20 x + 100\right) = 100 - 70 = 30$

${\left(x - 10\right)}^{2} = 30$ ->$\left(x - 10\right) = \pm \sqrt{30}$

$x = 10 \pm \sqrt{30}$