How do you condense $7 ln x - 2 ln y$ $7lnx-2lny$ ?

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Answer 1 · 2016-03-28T08:35:59

$ln (\frac{x^{7}}{y^{2}})$ $ln(x^7/y^2)$

We may use the identities $ln a - ln b = ln (\frac{a}{b})$ $lna-lnb=ln(a/b)$ and $a ln b = {ln a}^{b}$ $alnb=lna^b$ .

Using them $7 ln x - 2 ln y$ $7lnx-2lny$

= ${ln x}^{7} - {ln y}^{2}$ $lnx^7-lny^2$

= $ln (\frac{x^{7}}{y^{2}})$ $ln(x^7/y^2)$

How do you condense 7lnx-2lny 7lnx−2lny7lnx-2lny ?