# How do you convert (0, -5) into polar form?

Sep 12, 2017

see below

#### Explanation:

Use the formulas ${r}^{2} = {x}^{2} + {y}^{2} , \tan \theta = \frac{y}{x}$

${r}^{=} \sqrt{{0}^{2} + {\left(- 5\right)}^{2}} = \sqrt{25} = 5$

$\tan \theta = - \frac{5}{0} = u n \mathrm{de} f$

$\theta = - \frac{\pi}{2} + 2 \pi n \mathmr{and} \frac{3 \pi}{2} + 2 \pi n$

So one possible solution is $\left(5 , - \frac{\pi}{2}\right)$