Question

How do you convert `(0, -5)` into polar form?

Answer 1

see below

Explanation:

Use the formulas `r^2=x^2+y^2, tan theta=y/x`

`r^=sqrt(0^2+(-5)^2)=sqrt25 =5`

`tan theta =-5/0=undef`

`theta=-pi/2+2pin or (3pi)/2+2pin`

So one possible solution is `(5, -pi/2)`