Question

How do you convert `(0, 6)` to polar form?

Answer 1

See explanation.

Explanation:

graph{(x^2+(y-6)^2-0.1)=0 [-20.27, 20.26, -10.14, 10.13]}

The point `(0,6)` lies on the positive (upper) part of `Y` axis, so the angle between the positive part of the `X` axis and the line containing the point is `pi/2`, the distance between the point `(0,6)` and the origin is `r=6`, so the polar coordinates of `(0,6)` are:

`{(r=6),(varphi=pi/2):}` ##