How do you convert # (0, pi/6)# to rectangular form?

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Answer 1 · 2018-03-30T09:45:25

#color(blue)(0,0#

#(r,theta)# and for Cartesian we have #(x,y)#

We know using trigonometry that:

#x=rcos(theta)#

#y=rsin(theta)#

#:.#

#(0,pi/6)#

#r=0#

#theta=pi/6#

Using these values:

#x=0*cos(pi/6)=>x=0#

#y=0*sin(pi/6)=>y=0#

So coordinates are:

#color(blue)((0,0)#

This could have been solved by just noting that the radius is zero, and this can only mean we are at the origin.