How do you convert #(2, (11pi)/6)# from polar to cartesian coordinates?

1 Answer
Fleur
Aug 29, 2017

#(sqrt 3, -1)#

Explanation:

#(2, (11pi)/6)# is in the polar form #(r, theta)#, and we have to convert it into the Cartesian form #(x,y)#. We can do this by using the following formulas:

#x = r cos theta#

#y = r sin theta#

In this case, #r = 2# and #theta = (11pi)/6#.

#x = 2 cos ((11pi)/6) = 2 * sqrt3/2 = sqrt3#

#y = 2 sin ((11pi)/6) = 2 * -1/2 = -1#

The Cartesian coordinate is #(sqrt 3, -1)#.

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