How do you convert $(-2, 2)$ to polar form?

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Answer 1 · 2016-05-02T09:44:10

$(-2,2)$ in polar form is $(2sqrt2,(3pi)/4)$

$(a,b)$ in polar form is $(r,theta)$ where $r=sqrt(a^2+b^2)$ and $tantheta=b/a$

Hence $(-2,2)$ in polar form is $(r,theta)$ where

$r=sqrt((-2)^2+2^2)=sqrt(4+4)=sqrt8=2sqrt2$ and

$tantheta=2/(-2)=-1=(3pi)/4$

Hence $(-2,2)$ in polar form is $(2sqrt2,(3pi)/4)$

How do you convert (-2, 2) (-2, 2) to polar form?