How do you convert $(-3, 3)$ to polar form?

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Answer 1 · 2016-06-26T14:57:45

$(3sqrt2, (3pi)/4)$

The given

$x=-3$ and $y=3$

$r=sqrt(x^2+y^2)=sqrt((-3)^2+(3)^2)=sqrt(9(2))=3sqrt2$

$theta=arctan(y/x)=arctan(3/(-3))=arctan(-1)=(3pi)/4$

God bless....I hope the explanation is useful.

How do you convert (-3, 3) (-3, 3) to polar form?