Question

How do you convert `θ = (3 pi )/ 4` into cartesian form?

Answer 1

`theta =(3pi)/4 -> P_1->(x,y)=(rcos((3pi)/4),rsin((3pi)/4))`

Explanation:

Let `(0,0)" to point "(x,y)" be "r`

Then we have `x=rcos(theta)" ; "y=rsin(theta)`

So `theta =(3pi)/4 -> P_1->(x,y)=(rcos((3pi)/4),rsin((3pi)/4))`