How do you convert $(-5, π/4)$ to rectangular form?

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Answer 1 · 2016-02-23T09:05:23

Coordinates in rectangular form are $(-5/sqrt2, -5/sqrt2)$

To convert $(−5,pi/4)$ to rectangular form, we use relations $x=rcostheta$ and $y=rsintheta$

Hence $x=(-5)cos(pi/4)$ and $y=(-5)sin(pi/4)$

or $x=-5/sqrt2$ and $y=-5/sqrt2$

Hence coordinates in rectangular form are $(-5/sqrt2, -5/sqrt2)$

How do you convert (-5, π/4)(-5, π/4) to rectangular form?