How do you convert $9=(5x+y)^2-2y+x$ into polar form?

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Answer 1 · 2018-05-14T08:20:27

$r=9/(r(5costheta+sintheta)^2-2sintheta+costheta)$

For this we will need:
$x=rcostheta$
$y=rsintheta$

Substituting these equations gives us:
$9=(5rcostheta+rsintheta)^2-2rsintheta+rcostheta$

$9=r^2(5costheta+sintheta)^2-2rsintheta+rcostheta$

$9=r(r(5costheta+sintheta)^2-2sintheta+costheta)$

$r=9/(r(5costheta+sintheta)^2-2sintheta+costheta)$

How do you convert 9=(5x+y)^2-2y+x9=(5x+y)^2-2y+x into polar form?