How do you convert #e^(3-4i)# into cartesian form?

Question

5302 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-25T16:44:38

#e^3(cos 4-i sin 4)=-13.13-i 15.20#., nearly

#e^(3-4i)#

#=e^3 e^((-4)i)#

#=e^3(cos(-4)+i sin (-4)#

#=e^3(cos 4 - i sin 4)#

#20.0855(cos (229.2^o)- i sin (229.3^o))#

#=-13.13-i 15.20#., nearly

-