How do you convert $(-pi, -3pi/4)$ to rectangular form?

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Answer 1 · 2016-11-17T14:25:54

The answer is $=(pi/sqrt2,pi/sqrt2)$

To convert from polar coordinates $(r,theta)$ to rectangular coordinates $(x,y)$ , we use the following equations

$x=rcos theta$

$y=rsintheta$

Here, $(r,theta)=(-pi,-3pi/4)$

Therefore, $x=-pi*cos((-3pi)/4)=-pi*-sqrt2/2=pi/sqrt2$

$y=-pi*sin ((-3pi)/4)=-pi*-sqrt2/2=pi/sqrt2$

So the rectangular coordinates are $(x,y)=(pi/sqrt2,pi/sqrt2)$

How do you convert (-pi, -3pi/4) (-pi, -3pi/4) to rectangular form?