How do you convert $r = 6 sin (θ)$ $r=6sin(theta)$ to rectangular form?

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How do you convert $r = 6 sin (θ)$ $r=6sin(theta)$ to rectangular form?

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Answer 1 · 2016-05-12T18:45:17

$x = 6 \cdot cos (θ) sin (θ), y = 6 \cdot {sin (θ)}^{2}$ $x=6*cos(theta)sin(theta), y = 6*sin(theta)^2$

Explanation:

The pass equations are: $x = r \cdot cos (θ), y = r \cdot sin (θ)$ $x=r *cos(theta),y=r *sin(theta)$ then substituting we get $x = 6 \cdot cos (θ) \cdot sin (θ), y = 6 \cdot {sin (θ)}^{2}$ $x=6*cos(theta)*sin(theta), y = 6*sin(theta)^2$

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How do you convert $r = 6 sin (θ)$ $r=6sin(theta)$ to rectangular form?

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Explanation:

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Math

Humanities

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How do you convert r=6sin(theta)r=6sin(θ)r=6sin(theta) to rectangular form?

1 Answer

Explanation:

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How do you convert $r = 6 sin (θ)$ $r=6sin(theta)$ to rectangular form?