How do you convert #(theta)=(-7pi)/4# into cartesian form?

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Answer 1 · 2017-09-11T19:37:13

see below

Use the formula #tan theta =y/x#

#theta=tan^-1 (y/x)#

Therefore,

#theta=(-7pi)/4#

#tan^-1 (y/x)=(-7pi)/4#

#y/x=tan((-7pi)/4)#

#y/x = 1#

#:.y=x#