# How do you convert #Theta=-pi/6# into cartesian form?

##### 1 Answer

Jun 3, 2016

I adhere to the convention that r is modulus (length), and so, r is non-negative.

#### Explanation:

Use theta = tan^(-1)(y/x)#

Here,

So,

This line is restricted to the 4th quadrant.

The other half is given by the polar equation

Note that

You can include r = 0 ((x, y)=(0, 0)) as the limiting end-point, for each

half.