How do you convert #Theta=-pi/6# into cartesian form?
I adhere to the convention that r is modulus (length), and so, r is non-negative.
Use theta = tan^(-1)(y/x)#
This line is restricted to the 4th quadrant.
The other half is given by the polar equation
You can include r = 0 ((x, y)=(0, 0)) as the limiting end-point, for each