# How do you convert #x^ 2 + y ^2 + 3y = 0# into polar form?

##### 1 Answer

Nov 12, 2016

#### Explanation:

The given equation

cartesian

graph{x^2+y^2+3y=0 [-10, 10, -5, 5]}

Let O be the pole ( origin ) and #P(r, theta) any point on the circle.

Then observing #triangle OPC is isosceles and projecting the equal

sides OC and CP on OP,

Easy to find that