How do you convert $y=(x-y)^2-xy$ into a polar equation?

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Answer 1 · 2016-02-02T11:57:35

here is how,

here,
$y=(x-y)^2-xy$

$or,y=x^2-2xy+y^2-xy$

$or,rsintheta=(x^2+y^2)-3xy$

$or,rsintheta=r^2-3rcosthetarsintheta$

$or,2rsintheta=2r^2-3*r^2*2costhetasintheta$

$or,2sintheta=2r-3rsin2theta$

How do you convert y=(x-y)^2-xy y=(x-y)^2-xy into a polar equation?