How do you cube #(x+1)^3#?
You should find:
One way to deal with it is to "break" it into chunks and use the "distributive" property, as:
let us do the first 2:
now let us multiply the remaining 2:
There are two ways: do it in steps, or use the Pascal triangle.
First you take the square, and then again multiply by
In the third row of the Pascal triangle you will find the numbers
These are the coefficients for the powers of
You can use the triangle for any power of
(you'll notice that any number in a row is the sum of the two numbers above it, and the top
(it would be hard to do this step by step)