How do you describe the end behavior of f(x)=x^5-4x^3+5x+2?

1 Answer
Nov 8, 2017

See below.

Explanation:

For end behaviour of a polynomial we only need to be concerned with the degree and leading coefficient as we approach oo and -oo

For this example the degree is 5 and leading coefficient is 1.

as x-> oo , x^5-> oo

as x-> -oo , x^5-> -oo

(a negative value raised to an odd power is always negative )

So range of function is:

[y in RR }

Graph: graph{x^5-4x^3+5x+2 [-14.24, 14.24, -7.12, 7.13]}