How do you describe the end behavior of $y=4x^5+2x^4-3x-1$ ?

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Answer 1 · 2017-06-11T12:02:52

End behaviour: Down in 3rd quadrant and up in 1st quadrant

Here Degree is odd $(5)$ .

Leading coefficient is $+$ .

End behaviour: Down in 3rd quadrant and up in 1st quadrant

As $x -> -oo , y -> -oo$ and

as $x -> oo , y -> oo$ graph{4x^5+2x^4-3x-1 [-10, 10, -5, 5]} [Ans]

How do you describe the end behavior of y=4x^5+2x^4-3x-1y=4x^5+2x^4-3x-1?