Question

How do you describe the solutions for a quadratic equation with a discriminant of -6?

Answer 1

Roots will be complex conjugate numbers.

Explanation:

If the discriminant is `-6`, roots will be complex conjugate, assuming coefficients of `x^2`, `x` and constant term are real .

As roots of the quadratic equation `ax^2+bx+c=0` are given by

`(-b+-sqrt(-6))/(2a)`

roots will be `-b/(2a)+-isqrt6/(2a)`