# How do you describe the solutions for a quadratic equation with a discriminant of -6?

Mar 9, 2017

Roots will be complex conjugate numbers.

#### Explanation:

If the discriminant is $- 6$, roots will be complex conjugate, assuming coefficients of ${x}^{2}$, $x$ and constant term are real .

As roots of the quadratic equation $a {x}^{2} + b x + c = 0$ are given by

$\frac{- b \pm \sqrt{- 6}}{2 a}$

roots will be $- \frac{b}{2 a} \pm i \frac{\sqrt{6}}{2 a}$